The diffraction grating

A diffraction grating is an optical device made up of a large number of equally spaced parallel slits. When monochromatic light (light of a single wavelength) passes through the grating, it is diffracted by each slit, and the diffracted waves interfere to produce a pattern of bright and dark fringes on a screen.

A clean, minimalist diagram showing a rectangular diffraction grating with several evenly spaced vertical slits. A single horizontal arrow labeled 'Monochromatic light' points toward the grating. On the other side, several diverging arrows show diffracted beams at different angles, with bright spots on a screen labeled 'Maxima'. Keep the design simple and modern.

The bright fringes, called maxima, occur at specific angles where the path difference between light from adjacent slits is an integer multiple of the wavelength. This constructive interference produces sharp, bright lines at certain angles.

Grating Equation

The condition for constructive interference (maxima) is given by the grating equation:

Formula
dsinθ=nλd \sin \theta = n\lambda

where:

  • dd = distance between adjacent slits (grating spacing)
  • θ\theta = angle at which the nnth order maximum occurs
  • nn = order of the maximum (an integer: 0, 1, 2, ...)
  • λ\lambda = wavelength of the light

A minimalist diagram showing two adjacent slits separated by distance 'd', with two rays emerging at an angle 'theta' to the normal. Indicate the path difference between the rays as 'nλ'. Use thin lines and clear labels, keeping the style modern and uncluttered.

The grating spacing dd is usually given by d=1Nd = \frac{1}{N}, where NN is the number of lines per metre on the grating.

Using a Diffraction Grating to Measure Wavelength

  1. Shine monochromatic light perpendicularly onto the grating.
  2. Observe the diffraction pattern on a screen or detector.
  3. Measure the angle θ\theta at which each bright fringe (maximum) appears.
  4. Use the known value of dd (from the grating's specification) and the measured θ\theta in the grating equation to calculate the wavelength λ\lambda.
Example

A grating has 5000 lines per cm. Monochromatic light produces a first-order maximum at θ=30\theta = 30^\circ. Find the wavelength.

  • N=5000N = 5000 lines/cm =5.0×105= 5.0 \times 10^5 lines/m
  • d=1/N=2.0×106d = 1/N = 2.0 \times 10^{-6} m
  • n=1n = 1
dsinθ=nλ    λ=dsinθd \sin \theta = n\lambda \implies \lambda = d \sin \theta λ=(2.0×106)×sin30=1.0×106 m=1000 nm\lambda = (2.0 \times 10^{-6}) \times \sin 30^\circ = 1.0 \times 10^{-6} \text{ m} = 1000 \text{ nm}

Key Points

  • The central maximum (n=0n=0) is always at θ=0\theta = 0^\circ.
  • Higher order maxima (n=1,2,...n=1,2,...) occur at larger angles.
  • The maximum possible value of nn is limited by sinθ1\sin \theta \leq 1.

A simple, modern diagram of a horizontal screen with a central bright spot labeled 'n=0' and two symmetrical bright spots on either side labeled 'n=1', 'n=2', etc. Show the angles θ from the central axis to each spot. Keep the design clean and minimalist.

Important

Always check that calculated values of sinθ\sin \theta do not exceed 1, as this would be physically impossible.

Exam Tip

When using the grating equation, ensure all quantities are in SI units (metres for dd and λ\lambda).

Summary

  • A diffraction grating produces sharp maxima at angles given by dsinθ=nλd \sin \theta = n\lambda.
  • Measuring the angle of these maxima allows the wavelength of light to be determined accurately.

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